Draw a schematic diagram of a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.use this circuit to find the value of the following:
a.current through each resistor
b. Total effective resistance of the circuit
Answers
Answer: a)
i) 0.6 A
ii) 0.3 A
iii) 0.2 A
b) Total Current=1.1 A
i) + ii) + iii) = 1.1 A
c) R=V/I
=6v/1.1A
=5.45 Ohms
This answer is 100•/• Correct
Answer:
current through each resistor is 1.1A and total effective resistance of the circuit is 5.45 ohm.
Explanation:
As per the data given in the question
we have to calculate the value of
a. current through each resistor
Draw a schematic diagram of a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.use this circuit to find the value of the following:
a.current through each resistor
b. Total effective resistance of the circuitb. Total effective resistance of the circuit
As per the question it is given that a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.
Given data
Number of cells =3
The voltage of each cell = 2V
The total voltage of the battery = 2*3=6V
Calculating the current through each resistor:
Let, the current is in the resistance
We know that the voltage (V) remains the same across each resistor (R) in a parallel combination.
The formula: I=V/R
so I1 = V/R1 = 6/10 = 0.6 A
I2 = V/R2 = 6/20 = 0.3 A
I3 = V/R3 = 6/30 = 0.2 A
Total current in the circuit = I1+I2+I3 = 1.1 A
Total effective resistance = 1/R = 1/R1+1/R2+1/R3
So, 1/R = 11/60
R=5.45 Ohm
Hence, current through each resistor is 1.1A and total effective resistance of the circuit is 5.45 ohm.
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