Physics, asked by Raawiya123, 10 months ago

Draw a schematic diagram of a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.use this circuit to find the value of the following:
a.current through each resistor
b. Total effective resistance of the circuit

Answers

Answered by SakthiAK47
47

Answer: a)

i) 0.6 A

ii) 0.3 A

iii) 0.2 A

b) Total Current=1.1 A

i) + ii) + iii) = 1.1 A

c) R=V/I

=6v/1.1A

=5.45 Ohms

This answer is 100•/• Correct

Answered by sadiaanam
0

Answer:

current through each resistor is 1.1A and total effective resistance of the circuit is 5.45 ohm.

Explanation:

As per the data given in the question

we have to calculate the value of  

a. current through each resistor

Draw a schematic diagram of a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.use this circuit to find the value of the following:

a.current through each resistor

b. Total effective resistance of the circuitb. Total effective resistance of the circuit

As per the question it is given that a circuit consisting of a battery of 3 cells of 2 V each a combination of three resistors of 10 ohm 20 ohm 30 ohm connected in parallel a plug key and an ammeter all connected in series.

Given data

R_{1}=10 Ohm

R_{2}= 20 OhmR_{3}=30 Ohm

Number of cells =3

The voltage of each cell = 2V

The total voltage of the battery = 2*3=6V

Calculating the current through each resistor:

Let, the current is I_{1},I_{2} and I_{3}   in the resistance  R_{1},R_{2} and R_{3}R_{1},R_{2} and R_{3}

We know that the voltage (V) remains the same across each resistor (R) in a parallel combination.

The formula: I=V/R

so I1 = V/R1 = 6/10 = 0.6 A

I2 = V/R2 = 6/20 = 0.3 A

I3 = V/R3 = 6/30 = 0.2 A

Total current in the circuit = I1+I2+I3 = 1.1 A

Total effective resistance = 1/R = 1/R1+1/R2+1/R3

So, 1/R = 11/60

R=5.45 Ohm

Hence, current through each resistor is 1.1A and total effective resistance of the circuit is 5.45 ohm.

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