Question

Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 5 ohm resistor, an 8 ohm resistor, and a 12 ohm resistor and a plug key, all connected in series​

Answer 1

Answer:

Given that,

Voltage = 2 V

Resistance R_{1}=5\ \OmegaR

1

=5 Ω

Resistance R_{1}=8\ \OmegaR

1

=8 Ω

Resistance R_{1}=12\ \OmegaR

1

=12 Ω

We know that,

Potential in parallel circuit :

The potential across in each resistance is same in parallel circuit.

Current in series circuit :

The current across in each resistance is same in series circuit.

We need to draw a schematic diagram of a circuit

According to given data,

Three resistance R₁, R₂ and R₃ connected in series with the battery and the potential of three cells of 2 V each.

The potential in the circuit is

V=V_{1}+V_{2}+V_{3}V=V

1

+V

2

+V

3

Put the value of potential

V=2+2+2V=2+2+2

V=6\ VV=6 V

So, The potential in the circuit will be 6 V.

In this circuit, the current will be same.

Hence, This is required answer.