Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 4
Ω resistor, 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series. [5]
(a)Calculate the current flowing through 4Ω resistor.
(b)Calculate the potential difference across 12Ω resistor.
(c)Calculate the equivalent resistance of the circuit.
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Answers
Explanation:
Given that,
Voltage = 2 V
Resistance R_{1}=5\ \text{\O}megaR
1
=5 Ømega
Resistance R_{1}=8\ \text{\O}megaR
1
=8 Ømega
Resistance R_{1}=12\ \text{\O}megaR
1
=12 Ømega
We know that,
Potential in parallel circuit :
The potential across in each resistance is same in parallel circuit.
Current in series circuit :
The current across in each resistance is same in series circuit.
We need to draw a schematic diagram of a circuit
According to given data,
Three resistance R₁, R₂ and R₃ connected in series with the battery and the potential of three cells of 2 V each.
The potential in the circuit is
V=V_{1}+V_{2}+V_{3}V=V
1
+V
2
+V
3
Put the value of potential
V=2+2+2V=2+2+2
V=6\ VV=6 V
So, The potential in the circuit will be 6 V.
In this circuit, the current will be same.
Hence, This is required answer.
Answer:
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Explanation:
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