Question

Draw a schematic diagram of a circuit consisting of a battery of three cells of 2V each, a 5Ω resistor, an

8Ω resistor, and 12Ω resistor, and a plug key, all connected in series?​

Answer 1

Explanation:

all resistance are in series

Answer 2

Explanation:

It is noted that the ammeter has been put in series with the circuit and the voltmeter has been put in a parallel with 120 resistor. (i) Calculation of current reading in the ammeter:

Here, R₁5, R₂ = 822, and R, 120 These three resistors are connected in series.

Total resistance, R = R₁ + R2 + Rs

= 5 + 8 + 12= 25 Ω

Potential difference, V = 6 V

Current, /=?

Applying Ohm's law,

V = IR

V 6

I = = 0.24 A R 25

Therefore, ammeter will show a reading of 0.24 A.

(ii) Calculation of potential difference reading across 12

a resistor.

Current,l=0.24A, Resistance, R Potential difference, V =?Applying Ohm's law

v=IR= 0.24 x 12= 2.88 V

Therefore, the voltmeter reading is 2.88

V.

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