Draw a schematic diagram of an electric circuit consisting of battery of five 2V cells, a 20 Ω resistor, a 30 Ω resistor, a plug key, all connected in series. Calculate the value of current flowing through the 20 Ω resistor and the power consumed by the 30 Ω resistor.
Answers
Answer:
Current Flowing Through 20Ω resistor
I = V/R
I = 10/20
Hence the current flowing is 0.5 Ampere.
Power consumed by the 30 Ω resistor
Power = Voltage × current.
Given Voltage = 10V; current = 0.5
⇒ Power = 10 × 0.5 = 5W
Hence power consumed by 30 Ω resistor is 5W.
Current = 0.5 A; Power consumed by 30 Ω resistor is 5W.
Explanation:
Given: Current flowing through 20 Ω resistor and 30 Ω resistor.
To find: Value of current and power consumed by resistor.
Please refer to the attached picture for the schematic diagram.
Potential difference = 30 - 20 = 10 V
Current flowing through the 20 Ω resistor can be calculated using the formula:
I = V / R
I = 10 / 20 = 0.5
So the current flowing it is 0.5 Ampere.
Power consumed by the 30 Ω resistor
Power = Voltage × current.
Power = 10 × 0.5 = 5W
Power consumed by 30 Ω resistor is 5W.