Question

Draw a schematic diagram of an electric circuit consisting of a battery of five 2v cells, a 20 ohm resistor, a 30ohm resistor, a plug key, all.connected on series. Calculate the value of current flowing through the 20 ohm resistor and the potential difference across the 30 ohm resistor.


Please solve

Answer 1

★ current = 0.5 A

★ potential difference= 15 V

★ refer to attachment

Answer 2

Concept:

• Ohm's law
• Resistances
• Potential difference
• V = IR
• Series combination of cells
• Series combination of resistors

Given:

• 5 2V cells are connected, net voltage = 5*2 = 10 V
• First resistance, R1 = 20 ohm
• Second resistance R2 = 30 ohm

Find:

• the value of the current flowing through the 20 ohm resistor
• The potential difference across the 30-ohm resistor.

Solution:

The resistors are connected in series, so the net resistance is the sum of the individual resistances.

Rnet = R1 +R2 = 20 + 30 = 50 ohm

The net potential difference provided by the cells = 10 V

The current I = V/R

I = 10/50 = 0.2 A

The potential difference across the 30 ohm resistor

V = IR2

V = 0.2 * 30

V = 6V

The current is 0.2 A and the potential difference across the 30 ohm resistor is 6 V.

#SPJ3