Question

. Draw a schematic diagram of an electric circuit (in the 'on' position) consisting a battery of five cells of 2V each, a 5 ohm resistor, a 8ohm and 12ohm resistor, and
a plug key, all connected in series. An ammeter is put in the circuit to measure
the electric current through the resistors and a voltmeter is connected so as to
measure the potential difference across the 12 resistor. Calculate the reading
shown by the
Ammeter
Voltmeter connected to 12 ohm resistor
​

Answer 1

Answer:

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Explanation:

10 V Battery ; Rest Components 

Equivalent resistance = R1 +R2 +R3

                                          = 5 + 10 + 15 

                                          = 30 Ω

Current in the circuit , I = V / R 

                            

(ii) Potential Differences across 5Ω  resistor , V = IR

                                           = 1/3 A × 5Ω

= 1.67 V