draw a schematic diagram of circuit consisting of a battery of four 2 V cells, a 5 ohm resistor, a 8 ohm resistor and a 12 ohm resistor , and an ammeter, all are connected in series.
● FIND THE READING OF VOLTMETER IF IT IS CONNECTED ACROSS 12 OHM
RESISTOR.●
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As per the data provided in the sum three resistors of 5Ω,10Ω and 15Ω are connected in series so the net resistance = 5Ω +10Ω+15Ω = 30Ω. Also given that five cells of 2 V are connected in series, So, the total voltage of the battery is 10V,according to Ohm's law V=IR and I=V/R On substituting resultant voltage(V) as 10 V and resultant resistance as 30Ω. I=10 V/ 30Ω. = 3.33 ampere
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