Question

Draw a segment BC = 6cm and angle B = 60° AC - AB = 4cm and with Figure ​

Answer 1

Step-by-step explanation:

With due thanks to Orlando Del Carmen for the figure, in triangle(ABP), m<BAP=60°-45°=15° & m<APB=180°-(45°+15°)=120°. With AP=1unit, BP/sin(15°)=AP/sin(45°) =>BP=sin(15°)/sin(45°)=0.366units

AB=AP²+BP²-2*AP*BP*cos(120°)=1.5 units. BC=3*BP=3*0.366=1.098 units.

In triangle(ABC), AC=AB²+BC²-2*AB*BC*cos(45°)=1.5²+1.098²-2*1.5*1.098*cos(45°)=1.1264.

AC/sin(45°)=AB/sin(m<ACB) => 1.1264/sin(45°)=1.5/sin(m<ACB) => m<ACB=arc_sin(1.5*sin(45°)/1.1264)=arc_sin(0.9416)=70° 19′ 42″

Trust this helps.