Draw a square of area 5 square centimetres in three different ways.
(Recall Pythagoras theorem)
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Make a line segment BC = 2 cm, and C draw AC ⊥ BC such that AC = 1 cm.
Join AB, here. AB = √(22 + 12) = √5 cm.
At points A and B, draw perpendiculars AP ⊥ AB and BQ ⊥ AB, such that. AP = BQ = AB.
Join PQ, ABQP is required square and area(ABQP) = (√5)2 = 5 cm.
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