Question

Draw a square whose area is 4cm and you have also to find the Perimeter for that square.

Answer 1

$\red{\underline{{ \bf Question }}}$

• Draw a square whose area is 4cm and you have also to find the Perimeter for that square.

$\underline {\underline{{\purple{ \sf Given }}}}$

• Area of Square = 4 cm

$\underline {\underline{{ \purple{\sf To \: Find }}}}$

• Contact the square with the area 4 cm
• Calculate Perimeter

$\underline {\underline{{ \green{\sf Constructing \: Square }}}}$

$\setlength{\unitlength}{1 cm}\begin{picture}(6,6)\put(2, 2){\line(0, 1){2}}\put(2, 4){\line(1, 0){2}}\put(4, 4){\line(0, -1){2}}\put(4, 2){\line(-1, 0){2}}\end{picture}$

$\underline {\underline{{ \green{\sf Calculating \: Perimeter }}}}$

• We know, that all the sides of square are equal
• So, we can say that all the sides of square are equal

We know that

Area of Square = (side)²

$\dashrightarrow \sf 4 = s^{2}$

∴ $\longrightarrow \sf s^{2} = 4$

$\longrightarrow \sf s = \sqrt{4}$

$\longrightarrow \sf s = 2$

∴ The Side of the square is 2 cm

$\blue{\sf We \: know, \: Perimeter \: of \: Square = 4 \times side}$

$\sf Perimeter = 4 \times 2$

$\sf Perimeter = 8$

Thus, we got the Perimeter which is 8 cm

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Answer 2

Step-by-step explanation:

Given: Draw a square whose area is 4cm² and you have also to find the Perimeter for that square.

To find: perimeter of square

Solution:

To construct the square ,first find the side of the square.

We know that area of square = side×side

Let side of square is a cm

${a}^{2} = 4 \\ \\ a = \sqrt{4} \\ \\ a = ± 2 \\ \\ \bold{a = 2\: cm}$

Discard the -ve value.

Side of square is 2 cm

Construct the square:

• Take a line segment AB of 2 cm.
• Draw 90° angle on both A and B.
• Measure 2 cm from compass, make arc of 2 cm on 90° line from A and the same process from B.
• Mark those points C and D respectively
• join C to D.
• Square ABCD is done.

Find perimeter:

Perimeter of square : 4× side

$= 4 \times 2 \\ \\ = 8 \: cm$

Thus,

Side of square = 2 cm

Perimeter of Square = 8 cm

Hope it helps you.