Draw a tangent segment of length √12cm to the circle with center O and radius 2 cm passing through the point P which lies in the exterior of the circle
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Correct option is C)
Let external point be B. OA be radius of circle.
Given:
OB=12.5 cm
AB=12 cm
In right triangle, AOB, by Pythagoras Theorem,
OB
2
=AB
2
+OA
2
AO
2
=OB
2
−OA
2
=12.5
2
−12
2
=12.25
∴AO=3.5 cm
Diameter=2(AO)=2(3.5)=7 cm
Let external point be B. OA be radius of circle.
Given:
OB=12.5 cm
AB=12 cm
In right triangle, AOB, by Pythagoras Theorem,
OB
2
=AB
2
+OA
2
AO
2
=OB
2
−OA
2
=12.5
2
−12
2
=12.25
∴AO=3.5 cm
Diameter=2(AO)=2(3.5)=7 cm
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