Draw a trapezium where AB =6.5cm , CD =10cm, angle CAB = 45° , angle CBA = 75°
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Trapezium ABCD is constructed where AB =6.5cm , CD =10cm, angle CAB = 45° , angle CBA = 75°
Step-by-step explanation:
Step 1 : Draw a line segment AB = 6.5 cm
Step 2 : Draw an angle of 45° at A on AB using protector
Step 3 : Draw an angle of 75° at B on AB using protector such that it intersect earlier angle drawn in step 2 at C
Now
Cass 1 : if AB || CD
Then Draw a line parallel to AB passing through C then take length CD = 10 cm on that line
Join AD
Case 2 : if BC || AD
Then draw a line parallel to BC passing through A
then draw an arch taking 10 cm length from C cutting the parrallel line at D
join CD
Trapezium ABCD is constructed
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