Draw a triangke ABC, right angled at B, such that AB = 3 cm and BC = 5 cm. Now construct a triangke PBQ ~ triangle ABC, each of whose sides is 7/4 times the corresponding side of triangle ABC
Answers
Answered by
0
Step-by-step explanation:
BQ=
5
7
BC=
5
28
=5.6
PB=
5
7
AB=
5
21
=4.2
On BA extended mark P at 4.2 cm from B on same side of A
On BC extended mark Q at 5.6 cm from B on same side of C
Join P,Q
∴△PBQ is formed
Answered by
0
Step-by-step explanation:
BQ=
5
7
BC=
5
28
=5.6
PB=
5
7
AB=
5
21
=4.2
On BA extended mark P at 4.2 cm from B on same side of A
On BC extended mark Q at 5.6 cm from B on same side of C
Join P,Q
∴△PBQ is formed.
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