Question

Draw a triangle ABC and form and exterior angle ACD now take a protector and measure angle ACD angle a and Angle B find us find the sum of angle a + Angle B and compare it with the measure of angle ACD do you observe the angle a CD is equal or nearly equal to angle a + Angle B

Answer 1

Answer:

An exterior angle of a triangle is equal to the sum of the opposite interior angles. 

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠B

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠BSo,

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠BSo,∠A+∠B=140∘

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠BSo,∠A+∠B=140∘as ∠A=∠B

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠BSo,∠A+∠B=140∘as ∠A=∠Bor,2∠A=140∘

An exterior angle of a triangle is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠BSo,∠A+∠B=140∘as ∠A=∠Bor,2∠A=140∘∠A=∠B=70∘

Step-by-step explanation:

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