Draw a triangle abc if angle b = 65°, bc = 6 cm and its perimeter is 15 cm.
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The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:
Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘
Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.
Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.
Step 5: Draw a line through C′ parallel to AC intersecting AB at A′.
The triangle A′BC′ is the required triangle
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