Draw a triangle ABC in which∆A=120° and AB=AC=3cm . Draw the bisector of angle A.
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Answer:
1.Draw a line segment AB=3cm
2. Using protractor from B measure from 0
∘
and mark a point at 120
∘
3.From the point A using compass draw an arc of length 3cm
∴AB=AC=3cm
4.Join BC
5.Draw an arc at ∠A
6.Bisect the arc at ∠A and name the point of intersection of the arc as D
7.Join AD
thereforeAD is the angle bisector.
Hence ∠BAD=∠DAC=60
∘
'
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