draw a triangle ABC in which a b is equal to 4 cm BC is equal to 5 cm and ac is equal to 6 CM then construct another triangle whose sides are 5 divided by 3 of the corresponding sides of triangle ABC
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AB=4 --second triangle 5/3*4=6.67
BC=5--second triangle 5/3*5=8.34
AC=10--second triangle 5/3*6=10
So Second triangle sides are
AB=6.67
BC=8.34
AC=10
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triangle ab'c' is the required triangle
ac'=10
ab'=6.6
ac'=10
ab'=6.6
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