draw a triangle ABC in which AB=5.1 cm BC =4.3 cm and angle B =60° .Draw the bisector of angle C and angle A of the triangle meeting at a point x .Measure angle CxA
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Construct BC = 6 cm
Construct an angle of 60° at B on BC.
Taking B as centre, with 9 cm radius, draw an arc , which cuts the ray of 60° angle, at X
Join X & C
Then draw perpendicular bisector of XC
Join A & C
So, ABC will be the required triangle
Since AC = AX ( as point ‘A’on perpendicular bisector remains equidistant from X & C )
But AX + AB = 9cm ( we constructed)
=> AC + AB = 9 cm
Construct an angle of 60° at B on BC.
Taking B as centre, with 9 cm radius, draw an arc , which cuts the ray of 60° angle, at X
Join X & C
Then draw perpendicular bisector of XC
Join A & C
So, ABC will be the required triangle
Since AC = AX ( as point ‘A’on perpendicular bisector remains equidistant from X & C )
But AX + AB = 9cm ( we constructed)
=> AC + AB = 9 cm
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