Question

Draw a triangle ABC in which AB = 5 cm, BC = 6 cm and ∠ABC = 60°. Then construct a triangle whose sides are $\frac{5}{7}$ times the corresponding sides of ∆ABC. ​

Answer 1

Answer:

FIGURE IS IN THE ATTACHMENT

Given , a ∆ ABC , in which BC = 6 cm , AB = 5 cm & ∠ABC = 60°,

Steps of construction:

1. Draw a line segment AB =5 cm.

2. From point P draw ∠ABY = 60° and cut off BC =6 cm from BY.

3. Join AC. Thus ∆ABC is a given Triangle.

4. Now from a draw anyway X making an acute ∠BAX with base AB on the side opposite to the vertex A.

5. Mark 4 points B1,B2,B3,B4 on AX such that AB1 = B1B2 = B2B3 = B3B4.

6.Join B4B and from B3 draw B3M || B4B intersecting AB at M.

7. From point M, draw MN || BC intersecting AC at N. Thus , ∆AMN  is the required triangle whose sides are 3/4 of the corresponding sides of ∆ABC.

hope it helps...................

Explanation:

Answer 2

Answer:

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