Question

Draw a triangle ABC in which AB=6cm,BC=7cm and angle B=45° .Then construct a triangle whose sides are 5/8 of the corresponding sides of the triangle ABC.

Answer 1

step 1. draw base BC=7cm
step 2.from B draw a ray BX at 45°
step 3.draw an arc AB of 6 cm on BX.
step 4. join AC=4.5cm

sides of 5/8 length
$xy= \frac{5}{8} \times 6 = 3.7 \\ yz= \frac{5}{8} \times 7 = 4.3 \\ zx = \frac{5}{8} \times 4.5 = 2.8$

steps of construction for another ∆
now with the new measurements draw triangle xyz,where
XY=3.7 cm
YZ=4.3 cm
ZX=2.8 cm
angle Y=45°

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