Question

Draw a triangle ABC, in which angle B = 65 degree. AB = 2cm and BC = 6cm. Measure AC​

Answer 1

Answer:

STEPS OF CONSTRUCTION

(i) Draw BC=6 cm.

(ii) Construct ∠CBX=60∘

(iii) Produce XB downwards to a point X'.

(iv) Set off BD=2 cm along BX'.

(v) Join CD.

(vi) Draw the perpendicular bisector of CD, meeting BX at A.

(vii) Join AC.

Then, ΔABC is the required triangle.

Verification :

On measuring, we find that AC=5.4 cm and AB=3.4 cm.

∴(AC-AB)=(5.4-3.4)cm=2 cm.

Justification :

Since A lies on the perpendicular bisector of CD, we have AD=AC. Now, BD=2 cm ⇒AD-AB=2 cm

⇒AC-AB=2cm[∵AD=AC].

Hence, ΔABC is the required triangle.

Step-by-step explanation:

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Answer 2

Answer:

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