Draw a triangle ABC in which BC = 4.8 cm , AB = 4.2 cm and angle B = 45°
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Step-by-step explanation:
Construct a line segment BC = 4.8cm Considering B as centre and any radius, construct an arc which intersects BC at point P Considering P as centre and same radius, construct an arc which intersects the previous arc at the point Q Considering Q as centre and same radius, construct an arc which intersects the arc in step 2 at the point R Considering R and Q as centres and radius more than half of RQ, construct arcs intersecting each other at the point S Join BS which intersects the arc in step 2 at the point G so ∠SBC = 90o Considering P as centre and radius more than half of PG, construct an arc Considering G as centre and same radius, construct an arc which intersects the previous arc at the point X Join B and extend it so ∠B = 45o Draw ∠TCB = 90o Considering M and H as centres and radius more than half of MH, construct arcs which intersect each other at point Y Join CY and extend it so ∠C = 75o BX and CY intersects at point A after extending So, △ ABC is the required triangle Therefore, ∠A = 60oRead more on Sarthaks.com - https://www.sarthaks.com/728136/construct-a-abc-in-which-bc-4-8cm-b-45and-c-75-measure-a
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