Math, asked by Anonymous, 10 months ago

draw a triangle abc in which bc=5.2cm,angle b=100degee and angle a = 60 degree.draw the perpendicular from b to ac
explain

Answers

Answered by ItZCutiEGiRl
8

Hii mate here Ur Answer ☑️

Labeling thoda gadbad hai.... manage it

Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.

Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.2. At B, draw a line at 60 deg inclined to BC, using a protractor.

Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.2. At B, draw a line at 60 deg inclined to BC, using a protractor.∠C = 180 - ∠A - ∠B = 20°

Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.2. At B, draw a line at 60 deg inclined to BC, using a protractor.∠C = 180 - ∠A - ∠B = 20°3. Draw a line inclined at 20 deg. to CB, at point C using a protractor. This line is to cut the earlier line from B.

Draw a horizontal line. Using a scale or a compass (using arcs) locate B and C such that BC= 5.2 cm.2. At B, draw a line at 60 deg inclined to BC, using a protractor.∠C = 180 - ∠A - ∠B = 20°3. Draw a line inclined at 20 deg. to CB, at point C using a protractor. This line is to cut the earlier line from B.4. The point of intersection is point A.  The angle at A will be 100 deg. 

Hope uh will understand it very well....

Plz Mark me as brainliest ✌️❤️❤️☑️

Similar questions