Question

Draw a triangle ABC in which BC= 5.4cm, angle B = 45° and angle A = 115°. Now , construct a triangle similar to triangle ABC each of whose sides is 5/3 of the corresponding sides of triangle ABC

Answer 1

we draw line BC=6 cm;<B= 60 degrees & draw line BX=9 cm at 60 degrees to BC at B. we join CX;

we make <BXC=<XCB to meet line BX at A; since now XA=CX;

XB=9cm=BA+AX as AC=AX;

9 cm=BA+AC; REQD △ABC obtained

Answer 2

This picture has your answer..... Hope it helps :)