Draw a triangle ABC in which BC-6 cm,
CAS em and AB 4 cm Construct a triangle
5 ད
similar to it and of scale factor5/3
Answers
Steps of construction Draw a line segment BC = 6 cm. Taking Sand C as centres, draw two arcs of radii 4 cm and 5 cm intersecting each other at A. Join BA and CA. ΔABC is the required triangle. From B, draw any ray BX downwards making at acute angle. Mark five points B1, B2,B3, B4 and B5 on BX, such that BB, = B,B2 = B2B3 = B3B4 = B4B5. Join B3C and from B5 draw B5M || B3C intersecting the extended line segment BC at From point M draw MN || CA intersecting the extended line segment BA at N. Then, ΔNBM is the required triangle whose sides is equal to 5/3 of the corresponding sides of the ΔABC.Read more on Sarthaks.com - https://www.sarthaks.com/886052/draw-abc-in-which-bc-cm-ca-5cm-and-ab-4cm-construct-triangle-similar-to-it-and-of-scale-factorSteps of construction Draw a line segment BC = 6 cm. Taking Sand C as centres, draw two arcs of radii 4 cm and 5 cm intersecting each other at A. Join BA and CA. ΔABC is the required triangle. From B, draw any ray BX downwards making at acute angle. Mark five points B1, B2,B3, B4 and B5 on BX, such that BB, = B,B2 = B2B3 = B3B4 = B4B5. Join B3C and from B5 draw B5M || B3C intersecting the extended line segment BC at From point M draw MN || CA intersecting the extended line segment BA at N. Then, ΔNBM is the required triangle whose sides is equal to 5/3 of the corresponding sides of the ΔABC.Read more on Sarthaks.com - https://www.sarthaks.com/886052/draw-abc-in-which-bc-cm-ca-5cm-and-ab-4cm-construct-triangle-similar-to-it-and-of-scale-factor