Math, asked by KabirNagpal, 4 months ago


Draw a triangle ABC in which BC = 8 cm, ZB = 50° and ZA = 50°. Also bisect ZA and ZC.​

Answers

Answered by Anonymous
10

Answer:

 \huge \mathfrak \purple{answer}

Given;

BC=8 cm ,

∠B=50 degree and

angle A=50

We know for a ∆ABC

∠A+∠B+∠C=180

⇒∠C=180−∠A−∠B

⇒ C=180-50 (By plug the values)

⇒=80∠C=80

Step 1

=Draw line BC (8 cm)

Step 2

=From point B draw 50 degree line BX

Step 3

=From point C draw 80 degree line CY which cuts BX at A

Step 4

=And also bisect the angle A and C as soon in figure.

Now ABC is required triangle.

Attachments:
Answered by ⲎσⲣⲉⲚⲉⲭⳙⲊ
9

Answer:

 \huge \mathfrak \red{answer}

Given;

BC=8 cm ,

∠B=50 degree and

angle A=50

We know for a ∆ABC

∠A+∠B+∠C=180

⇒∠C=180−∠A−∠B

⇒ C=180-50 (By plug the values)

⇒=80∠C=80

Step 1

=Draw line BC (8 cm)

Step 2

=From point B draw 50 degree line BX

Step 3

=From point C draw 80 degree line CY which cuts BX at A

Step 4

=And also bisect the angle A and C as soon in figure.

Now ABC is required triangle.

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