Question

Draw a triangle ABC in which BC = 8 cm, ZB = 50° and ZA = 50°. Also bisect ZA and ZC.​

Answer 1

Answer:

Therefore ABCABC is required triangle.

Step-by-step explanation:

Given;

BC=8BC=8 cm , \angle B=50∠B=50 degree and \angle A=50∠A=50

We know for a \bigtriangleup ABC△ABC ,

\angle A+\angle B+\angle C=180∠A+∠B+∠C=180

⇒\angle C=180-\angle A-\angle B∠C=180−∠A−∠B

⇒\angle C=180-50-50∠C=180−50−50 (By plug the values)

⇒\angle C=80∠C=80

Step 1=Draw line BCBC (8 cm)

Step 2=From point BB draw 5050 degree line BXBX

Step 3=From point CC draw 8080 degree line CYCY which cuts BXBX at AA

Step 4=And also bisect the angle AA and CC as soon in figure.

Now ABCABC is required triangle.

Answer 2

First draw a line bc of 8 cm which will be the base of your triangle

Then with the help of a protector mark 50° from point b and c then joint it you will get an isosceles triangle

Now use a rounder take a small lenght make an arc at C now measure the lenght of ur arc nd cut from the two points where you made the arc at first then joint the point to the point c similarly do it with point A