Question

draw a triangle ABC such that BC = 3.6 CM AB=AC= 4.5 CM. Also draw the perpendicular bisector of BC does it passed through A​

pls show the whole procedure​

Answer 1

Step-by-step explanation:

$\sf\overbrace{Steps \: for \: Construction:}$

1. Draw a line segment AC = 5.4 cm.

2. With A as a center and radius 5 cm, draw an arc.

3. With C as a center and radius 3.6 cm, draw another arc, cutting the previous arc at B.

4. Join AB and CB. Then, ΔABC is the required triangle.

5. With B as center and radius measuring more than half of BC, draw arcs on both sides of BC.

6. With C as center and the same radius as before, draw arcs on both sides of BC, cutting the previous arcs at P and Q, as shown. Join PQ.

Thus, PQ is the required perpendicular bisector of BC, meeting BC at M.

Answer 2

given : ABC is a triangle &

BC = 3.6 CM , AB=AC= 4.5 CM

THEREFORE, AB= 4.5 & AC =4.5

CONSTRUCTION : DRAW AD perpendicular to BC

to prove : a perpendicular line AD Does it passes through A

proof : perpendicular means a line which divides in equal ration and Thier angles in triangle will be 90 °

Step-by-step explanation:

as shown in the figure

hope it helps you...

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