draw a triangle ABC such that BC = 4.5 CM angle b is equal to 40 degree AB - AC = 2 cm
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Answered by
2
Answer:
1. Construct a line segment BC of 4.5cm
2. Construct a 45
o
angle at B
3. Take the length of PB as 5.6cm.
4. Join PC
5. Construct a bisector at PC. The line will meet BP at point A. Join AC
We get the required triangle.
refer to the given attachment to see the diagram
hope it helps
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Answered by
3
Answer:
We are given BC = 4.5 cm,
∠B = 450 and AB - AC = 2.5 cm
Steps of Construction :
(i) Draw a ray BX and cut off a line segment BC = 4.5 cm from it.
(ii) Construct ∠XBY = 450
(iii) Cut off a line segment BC = 2.5 m from BY.
(iv) Join AC.
(v) Draw perpendicular bisector of CD cutting BY at a point A.
(vi) Join AC. So, ΔABC is the required triangle.
Attachments:
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