Question

draw a triangle ABC such that BC=5.2cm , angle B=100° and angle A=40°.

Answer 1

I will write the steps of construction ok
firstly draw a line segment BC= 5.2 cm
then at pt. B make an angle of 100 degree
at pt. C make an angle of 40 degree
[cuz sum of all angles of triangle =180°
therefore B-A=40°
at let the 2 line segments intersect each other at pt A
so ABC is required triangle

Answer 2

Step-by-step explanation:

draw line sagment of given cm

then at point b make 100 degree angle

first we find angle of c then the triangle is made

b-a=40

at point c make 40 degree

then a is find by owned