Question

draw a triangle ABC with b is 6 cm and angle abc is equal to 60 degree then construct 325 by 9 of the corresponding side of the triangle ABC

Answer 1

Step 1: Draw a line segment BC = 6 cm.

Step 2: At B, draw ∠CBE = 60°.

Step 3: Draw BF ⊥ BE.

Step 4: Draw the perpendicular bisector of BC intersecting BF at O.

Step 5: With O as centre and radius equal to OB or OC draw a circle.

Step 6: With D as centre and radius 5 cm, mark a point A on the circle.

Step 7: Join AB and AC. This gives the ΔABC.

Step 8: With B as centre and radius 8 cm, mark an arc which intersect BC produced in C'.

Step 9: Draw a line parallel to AC at C'.

Step 10: Extend the line segment BA, which intersect the line passing ttrough C' in A'.



Thus, ΔA'BC' is the required triangle.

Here, ΔA'BC' ∼ ΔABC. (AA Similarity)