Question

Draw a triangle ABC with BC=6cm, AB=5cm and ΔABC=60°. Then construct a triangle whose sides are 3/4 of the corresponding sides of the ΔABC.

Answer 1

Given,

In the triangle ABC,

BC = 6 cm
AB = 5 cm
angle ABC = 60°

Steps of construction :-

1. Draw a line segment AB = 5 cm .

2. From point A draw angle ABY = 60° and cut off BC = 6 cm from BY .

3. Join AC .

Thus ABC is a given triangle.

4. Now from A draw anyway X making an acute angle BAX with base AB on the side opposite to the vertex A .

5. Mark 4 points B1,B2,B3 and B4 on AX such that AB1 = B1B2 = B2B3 = B3B4 .

6. Join B4B and from B3 draw B3M || B4B intersecting AB at M .

7. From point M,draw MN || BC intersecting AC at N .

Thus, AMN is the required triangle whose sides are 3/4 of the corresponding sides of the given triangle ABC.



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