Question

Draw a triangle ABC with BC = 7 cm, ∠ B = 45° and ∠C = 60°. Then construct another triangle, whose sides are $\frac{3}{2}$ times the corresponding sides of ΔABC

Answer 1

Hey Sangam!!!
Here's Your answer

Steps of Construction.
1. Draw BC=7cm and extend it to Y.
2.Construct an angle of 45° on pt.B and an angle of 60° on point C, and join them.
3.Mark the inter section as pt. A.
4.Now draw any acute angle( <90°) at B.
5.Mark pts. B1, B2, B3 such that BB1=B1B2=B2B3.
6.Join B2 and C and draw a line B3C' parallel to it.
7.Now Draw C'A' parallel to AC.

Therefore,∆A'BC' is the required triangle.

The figure is in the attachment.

Hope it helps you :)

Answer 2

Answer:

u are wrong ❌❌................