Math, asked by rekhagowda800, 4 months ago

draw a triangle ABC with bc=7cm B =45degree, C=60degree then construct another triangle whose sides 2 half times of the corresponding ​

Answers

Answered by ghoshsubhasish168
0

Step-by-step explanation:

In order to construct △ABC, we follow the following steps :

STEP I Draw BC=7 cm.

STEP II At B construct ∠CBX=45

o

and at C construct

∠BCY=180

o

−(45

o

−105

o

)=30

o

Suppose BX and CY intersect at A.△ABC so obtained is the given triangle.

To construct a triangle similar to △ABC, we follow the following steps.

STEP I Construct an acute angle ∠CBZ at B on opposite side of vertex A of △ABC.

STEP II Mark-off four (greater 4 of and 3 in

3

4

) points B

1

,B

2

,B

3

,B

4

on BZ such that

BB

1

=B

1

B

2

=B

2

B

3

=B

3

B

4

.

STEP III Join B

3

(the third point) to C and draw a line through B

4

C parallel to B

3

C, intersecting the extended line segment BC at C.

STEP IV Draw a line through C parallel to CA intersecting the extended line segment BA at A.

Triangle ABC so obtained is the required triangle such that

AB

AB

=

BC

BC

=

AC

AC

=

3

4

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