Draw a triangle ABC with BC is equal to 6 cm AB is equal to 5 cm and angle ABC is equal to 60 degree then construct a triangle whose sides are 3 by 4 of corresponding side of the triangle ABC
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hey ......
refer to the attachment for diagram ...
Steps of construction :-
• Draw a line segment BC = 6cm .Taking B as centre draw 60° and mark it of 5cm at A .
• join CA .
• Draw an an acute angle of any measure at B .
• Mark 4 points on it .name it B1 B2 B3 And B4 . Such that B1 = B2 = B3 = B4 .
• join B4C
• Draw B3C' || B4c
•Draw C'A' || CA .
• Hence A'BC' is the required triangle .
hope it helps uh ...
nd plz mark as brainliest ....
refer to the attachment for diagram ...
Steps of construction :-
• Draw a line segment BC = 6cm .Taking B as centre draw 60° and mark it of 5cm at A .
• join CA .
• Draw an an acute angle of any measure at B .
• Mark 4 points on it .name it B1 B2 B3 And B4 . Such that B1 = B2 = B3 = B4 .
• join B4C
• Draw B3C' || B4c
•Draw C'A' || CA .
• Hence A'BC' is the required triangle .
hope it helps uh ...
nd plz mark as brainliest ....
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pinky544120:
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