Question

"Draw a triangle ABC with side BC=6.5cm, ∠B=30°, ∠A =105°. Then construct another triangle whose sides are 3/4 times the corresponding sides of the triangle ABC.

Answer 1

Δ ABC with side BC=6.5cm, ∠B=30°, ∠A =105° constructed also its 3/4 triangle is constructed

Step-by-step explanation:

∠B=30°, ∠A =105°

∠A + ∠B + ∠C = 180°

=> ∠C = 45°

Step 1 : Draw a line segment BC = 6.5 cm using ruler

Step 2 : Draw a line at angle 30° using protector at B

Step 3 : Draw a  line at angle 45° using protector at C such that it cuts earlier drawn line at A

ΔABC is constructed

To draw 3/4 time  the corresponding sides of the triangle ABC.

Draw an acute angle at BC at B oppsoite to the side vertex A

take some length and take one one by one 4 time on line

join last point with C

take parallel line to this line joining BC at some point D

BD = (3/4) BC

now Draw 45° angle at BD intersecting AB at point E

ΔBDE = (3/4) BCA