draw a triangle ABC with side BC=6cm AB=5cm and angle ABC=60° then construct a triangle whose sides are 3/5 of the corresponding sides of the triangle ABC
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Answer:
Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60
∘
Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Step 3: Locate 4 points, B
1
,B
2
,B
3
,B
4
on line segment BX.
Step 4: Join B
4
C and draw a line through B
3
, parallel to B
4
C intersecting BC at C
′
.
Step 5: Draw a line through C
′
parallel to AC intersecting AB at A
′
.
Step-by-step explanation:
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