Question

draw a triangle ABC with side BC=7 cm angle B = 45 degree angle A = 105 Then construct a trianglewhose sides are 4/3 times the corresponding sides of triangle ABC

Answer 1

$\huge{Steps\: of \: construction }$

☆ Draw a line segment BC = 7 cm .

☆ By using a compass , take B as contre and make 45° .

☆ Take C as centre and make 30°.

☆ Name the meeting point of both line segment as A.

☆ Now , ABC is the given triangle .

☆ Now , by taking B as centre make an acute angle of any measure .

☆ Mark 4 points on it named B1 , B2 , B3 AND B4 .

☆ Join B3C .

☆ Make B4C'||B3C.

☆ Now , Make C'A' parallel to CA .

☆ Join A'BC' .

☆ A'BC' Is the required triangle .