Question

· Draw a triangle ABC with side BC=7 cm, angle B = 45°, angle A = 105, then construct a
triangle whose side are 4by5 times the corresponding sides of triangle ABC.
On​

Answer 1

Answer:

First draw base BC then by rounder construct an angle at B of 45 degree.At angle C draw a angle 30 degree because by angle sum property of triangles A+B+C=180

therefore angle C will be of 30 degree.You will get A when both these lines are intersected.

FOR DRAWING 4/5 OF CORRESPONDING SIDE

Make an angle of 45 degree in downwards side.

From rounder keep a certain distance(ex-1cm)

Cut 5 arc in that line.

Mark then B1,B2,B3,B4 and B5.

Join B5 and C

From B4 draw a line parallel to B5

It will intersect BC at some point

Mark it E

You will get BE as 4

and BC as 5