Question

draw a triangle ABC with side BC is equal to 7 cm angle b is equal to 45 degree angle is equal to 105 degree then construct a triangle whose sides are 4 by 3 times the corresponding side of triangle ABC​

Answer 1

Step-by-step explanation:

Given ∠B = 45, ∠A = 105

Since sum of all interior angles in triangle is equal to 180

=> ∠A + ∠B + ∠C = 180

=> 105 + 45 + ∠C = 180

=> 150 + ∠C = 180

=> ∠C = 180 - 150

=> ∠C = 30

Construction:

1. Draw a triangle ABC having side BC = 7 cm, ∠B = 45, ∠C = 30

2. Now, draw a ray BX making an acute angle with BC on the opposite side of vertex A

3. Now, locate 4 points B1 ,B2 , B3 ,B4 on BX

4. Join B3 X and draw a line through B4 parallel to B3 C intersecting extended BC at C1

5. Now, through C1 , draw a line parallel to AC intersecting extended line segment at C1 .

Now, triangle A1 B1 C1 is the required triangle.

MARK IT AS BRAINLIEST

Answer 2

Answer:

A'B/AB=A'C'/AC=BC'/BC=4/5 ....