Draw a triangle ABC with sides 6 cm, 8 cm and 9 cm and then construct a triangle similar to triangle ABC whose sides are 3 / 5 of the corresponding sides of triangle ABC.
Answers
Here's the construction
Answer:
Step-by-step explanation:
3/5 means smaller triangle than the original triangle
Steps of construction
1. Draw a line ad 9 cm
2. From A point measure 6 cm in the compass n draw an arc.
3. From B point measure 8 cm and draw an arc
4. Where the arc meet that is C point
Join AC and BC
5. From A point draw an acute angle ( no meet to measure exactly, just construct it less than 90°)
6. Take any measurement and from a point draw a small arc
Mark it A1
7. Keeping the distance constant draw a total of five arcs. As in the ratio denomination is five.
8. Join A5 and B point.
9. Measure the angle created by A A5 B by compass.
10. From A3 point draw an arc which is equivalent to the angle measured.
11. Find the distance between the angle created in A A5 B point.
12.In A3 where the arc intersects at A to A5 line , from that point cut the arc.
13. The point of intersection of both arcs and A3 join those both till it touches AB line.
14. Repeat this with B point too.
15.join the both arcs you get to AC line at C1.
Therefore A B1 C1 is 3 /5 of ABC
Thank you
Hope it helps u
Plz don't mind if my language is not clear but seeing the images plz try to understand it.
