Question

draw a triangle ABC with sides 6cm,8cm and 9cm and then construct a triangle similar to triangle ABC whose sides are 3/5 of the corresponding sides of triangle ABC

Answer 1

Answer:

Step-by-step explanation: Steps to draw ΔABC

1. Draw line BC of side 6 cm

2. From B draw an arc of 8 cm and from C draw an arc of 9 cm

3. The point where two arc intersect. name that point A

4. Join B and C to A

∴  Δ ABC required triangle

Now we need to make a triangle which is 3/5 times its size.

∴ scale factor 3/5 < 1

Steps of construction

1. Draw any ray BX making an acute angle with BC on the side opposite to the vertex A

2. Mark 5 points B₁, B₂,B₃,B₄,B₅ ON BX

3. Join B₅C and draw a line through B₃ parallel to B₅C₁

4. Draw a line through C' parallel to the line AC to intersect BA at A'

Thus, Δ A'B'C' is the required triangle.

Answer 2

Answer:

Step-by-step explanation:

Let’s first construct triangle ABC with sides 6cm, 8cm, 9cm

Steps to draw Triangle ABC

1. Draw base AB Of side 6 cm

2. With A as center , and 8 cm as radius, draw an arc

With B as center, and 9 cm  as radius, draw  an arc  

3.Let C be the point where the two arcs intersect. Join AC&BC