Question

Draw a triangle in which AB =5cm,BC=6cm and angle <APB=60°.construct a triangle whose sides are 5/7 times the corresponding sides of triangle ABC​

Answer 1

Answer:

The ΔA′BC′ whose sides are 43 of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B1,B2,B3,B4 on line segment BX.

Step 4: Join B4C and draw a line through B3, parallel to B4C intersecting BC at C′.

Step 5: Draw a line through C′ parallel to AC intersecting AB at A′.

The triangle A′BC′ is the required triangle.

Step-by-step explanation:

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