draw a triangle of angles 30 degree 40 degree and 110 degree and circum
radius3 cm
Answers
Answered by
0
Answer:
(b) Steps of construction:
1. Extend OA and draw perpendicular to it through A.
2. Extend OB and draw perpendicular to it through B.
3. In the same way draw perpendicular to OC through C.
Let the points of intersection of these perpendicular be P, Q and R, so we get the required ΔPQR.
(c) In the quadrilateral PAOC,
m∠AOC=120
o
⇒m∠P=180
o
−120
o
=60
o
.... (opposite angles of a quadrilateral are suplementary)
In the same way, m∠Q=180
o
−140
o
=40
o
And, m∠R=180
o
−100
o
=80
o
Similar questions