Math, asked by shabnashaharbanm, 9 months ago

Draw a triangle of perimeter 10cm and side in ratio 3:4:5?

Answers

Answered by ROCKSTAR1OO8
8

Answer:

LET THE LENGTH OF SIDES BE x

now

3x+4x+5x=10

12x=10

x=10/12

x=5/6

first side= 3x=3*5/6=5/2=2.5cm

2nd side= 4x=4*5/6=10/3=3.3cm

3rd side=5x=5*5/6=25/6=4.1cm

STEPS OF CONSTRUCTION

DRAW AB OF LENGTH 2.5 cm

MARK AN ARC OF LENGTH 3.3cm FROM A

MARK AN ARC OF LENGTH 4.1cm FROM B

THE POINT AT WHICH BOTH ARC MEET NAME IT AS C

NOW CONNECT ALL THREE POINTS.

PLEASE MARK ME AS BRAINLIEST

Step-by-step explanation:

Answered by prazia
0
Let the angles of the given triangle be 3x, 4x and 5x
Then, 3x + 4x + 5x = 180o
Therefore, x = 15
Hence the angles are 45o, 60o and 75o

Steps of construction.

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