Question

Draw a triangle of sides 3,4,6 cm.Draw three different right triangles of the same area

Answer 1

Using Heron’s formula to find the area of the triangle

 

s = ½(3+4+6)

 

  = 6.5

 

 

Area = root (6.5)(6.5-3)(6.5-4)(6.5-6)

 

       = 5.33

 

 

The other three triangles are right angled and must have area =  5.33

 

First triangle:

Base = 4, height = 2.8

 

Second triangle:

 

Base = 5, height = 2.1

 

 

Third triangle:

 

Base = 6, height = 1.8

Answer 2

Answer:

area of triangle=√s(s-a)(s-b)(s-c)

                       =√6.5(6.5-3)(6.5-4)(6.5-6)

                        =√6.5(3.5)(2.5)(0.5)

                        =√28.4375

                        =5.332

Step-by-step explanation:

sum of all triangles=($\frac{a+b+c}{2}$ )

                              =($\frac{3+4+6}{2}$ )

                               =$\frac{13}{2}$    =6.5

area of triangle=√s(s-a)(s-b)(s-c)

                       =√6.5(6.5-3)(6.5-4)(6.5-6)

                        =√6.5(3.5)(2.5)(0.5)

                        =√28.4375

                        =5.332

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