Question

Draw a triangle of sides 3, 4 and 6 centimetres.
Draw three different right triangles of the same
area.​

Answer 1

Correct Question:

Draw a triangle of sides 3, 4 and 6 centimetres.

Draw three different right triangles of the same

area.

Solution:

Using heron's formula we have to find the area of the triangle.

s = ½(3+4+6)

 

  = 6.5

$\implies\sf{Area = root (6.5)(6.5-3)(6.5-4)(6.5-6) } = 5.33$

So, the other three right angle triangles are right angled must have the area = 5.33

So the frist triangle which is 3cm

Base = 4 , height = 2.8

The second triangle which is 4cm

Base = 5, height = 2.1

The third triangle which is 6cm

Base 6 , height = 1.8

(Note : Traingles are in the attachment for you're understanding )