draw a triangle of sides 6cm,5cm,4cm.and draw an isosceles triangle of the same area
Answers
Answer:
1) The dimensions of the triangle are 6 cm, 5 cm and 4 cm.
Steps of construction:
(i) Draw a line segment, say PQ, of length 4 cm.
(ii) Taking P as the center and radius 5 cm, draw an arc with the help of a compass.
(iii) Taking Q as the center and radius 6 cm, draw an arc with the help of a compass.
(iv) Let the two arcs intersect at point R.
(v) Now join PR and QR.
Hence, Δ PQR of dimensions 4 cm, 5 cm and 6 cm is constructed.
2) Constructing isosceles triangle of the same area.
Steps of construction:
(i) Draw a line xy passing through R and parallel to PQ.
{∵ The triangles lying on the same base and between the same parallels are equal in area}
(ii) Draw a perpendicular bisector of PQ.
(iii) Let it intersect line xy at point H.
(iv) Join PH and QH.
{∵ Any point on the perpendicular bisector is equidistant from the end points of the line segment}
Hence, ΔPQH is an isosceles triangle of same area as ΔPQR.
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Answer:
Step-by-step explanation: