Question

draw a triangle of sides 6cm,5cm, 7cm then construct a triangle similar to it whose sides are in the ratio of 2/5 of the original triangle pls fast.

Answer 1

Answer:

draw a triangle of sides 6cm,5cm, 7cm then construct a triangle similar to it whose sides are in the ratio of 2/5 of the original triangle.

Answer 2

$\huge\mathcal{\underbrace{CONSTRUCTION:-}}$

✍️ Let's first construct ∆ABC with sides 5cm, 6cm and 7cm .

✍️ Steps to draw ∆ABC :-

1. Draw base AB of side 5cm .
2. With ‘A’ as center and 6cm as radius, draw an arc .
3. With ‘B’ as center and 7cm as radius, draw an arc .
4. Let, ‘C’ be the point where the two arc's intersect .
5. Join AC and BC .

• Thus, ∆ABC is the required triangle

✍️ Now, Let's make a similar ∆ with scale factor = 2/5 .

✍️ Steps of Construction :-

1. Draw any ray AX making an acute angle with AB on the side opposite to the vertex ‘C’ .
2. Mark 5 points, i.e $\rm{A_1\:,\:A_2\:,\:A_3\:,\:A_4\:,\:A_5\:on\:AX\:}$, $\rm{\:so\:that\:;\:A_1A_2\:=\:A_2A_3\:=\:A_3A_4\:=\:A_4A_5\:.}$
3. Join $\rm{A_5B}$ and draw a line through $\rm{A_2\:parallel\:to\:A_5B}$, to intersect AB at B' .
4. Draw a line through B' parallel to the line BC to intersect AC at C' .

• Thus, ∆AB'C' is the required triangle

✍️ See the attachment construction .